3.47=4.9t^2

Solution for 3.47=4.9t^2 equation:

3.47=4.9t^2

We move all terms to the left:

3.47-(4.9t^2)=0

We get rid of parentheses

-4.9t^2+3.47=0

a = -4.9; b = 0; c = +3.47;
Δ = b2-4ac
Δ = 02-4·(-4.9)·3.47
Δ = 68.012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{68.012}}{2*-4.9}=\frac{0-\sqrt{68.012}}{-9.8}
=-\frac{\sqrt{}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{68.012}}{2*-4.9}=\frac{0+\sqrt{68.012}}{-9.8}
=\frac{\sqrt{}}{-9.8}
$